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Penjelasan dengan langkah-langkah:
5 soal Essay
18. Banyak keramik = keliling jalan
= 2 × [(20+1+1) + (10+1+1)]
= 2 × (22+12)
= 2 × 34
= 68 buah keramik ✔
19. Luas daerah tidak diarsir
= (7 + 12) × 10 – (12–7) × 10
2
= 19 × 5 – 50
= (19 – 10) × 5
= 45 cm²
20. Selisih luas dan keliling
= (12 × 25) – 2 × (15 + 20)
= 300 – 70
= 230
21. a. Panjang sisi atas
= 2 × 64 – 9
8
= 16 – 9
= 7 cm
b. Panjang sisi atas
= 2 × 48 – 9
8
= 12 – 9
= 3 cm
22. Keliling = 2 × (20+30+60 + 60/5)
= 2 × 122
= 244 cm
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